Matt Fellenz b41cce191c
Optimize .count() > 1 check (#1053)
This can be trivially optimized to `.nth(1).is_some()` which obviates evaluating every element in the iterator.
2023-05-01 13:29:59 +02:00
..
2023-05-01 13:29:59 +02:00
2023-04-26 15:54:05 +02:00